svn: missing argument: –password

I am currently setting up the Maven Release Plugin for a project which is stored in a SVN repository. The plugin needs to do modifications in the repository, for which it executes a svn command. The credentials it gets from ~/.m2/settings.xml, and the password is passed with the --password parameter. On the command line the password is masked.

Now I ran into the trouble that the svn command fails to execute with the message

svn: missing argument: --password

The complete output is:

[INFO] Executing: /bin/sh -c cd /Users/thoms/Development/projects/fornax/ws/fornax-parent && svn --username kthoms --password '*****' --no-auth-cache --non-interactive status
[INFO] Working directory: /Users/thoms/Development/projects/fornax/ws/fornax-parent
[INFO] ------------------------------------------------------------------------
[INFO] BUILD FAILURE
[INFO] ------------------------------------------------------------------------
[INFO] Total time: 7.031s
[INFO] Finished at: Wed Nov 26 09:39:38 CET 2014
[INFO] Final Memory: 10M/24M
[INFO] ------------------------------------------------------------------------
[ERROR] Failed to execute goal org.apache.maven.plugins:maven-release-plugin:2.5.1:prepare (default-cli) on project fornax-parent: Unable to check for local modifications
[ERROR] Provider message:
[ERROR] The svn command failed.
[ERROR] Command output:
[ERROR] svn: missing argument: --password
[ERROR] Geben Sie »svn help« für weitere Hilfe ein.

I could not explain this, since obviously a svn command was executed with passing my password. So I copied only the svn command and executed this only from command line:

svn --username kthoms --password MYPLAINPASSWORD --no-auth-cache --non-interactive update

Same effect.

Finally I found out that the password itself was causing the problem. Without telling too much I can say it started with the ‘#’ character. This lead to the fact that on shell this was interpreted as a comment. At the end this is completely logical, but I did not think about that scenario when choosing the password. And the error message was a bit misleading here.

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grep command to filter distinct values from XML tags

I have a ton of Oracle Forms XML export files and wanted to know, which different patterns occur for the value of the FormatMask XML attribute. The input looks as follows:

<Item Name="CREATION_DATE" UpdateAllowed="false" DirtyInfo="false" Visible="false" QueryAllowed="false" InsertAllowed="false" Comment="TABLE ALIAS&amp;#10;  FDA&amp;#10;&amp;#10;BASED ON TABLE&amp;#10;  TMI_FINANCIAL_DATA&amp;#10;&amp;#10;COLUMN USAGES&amp;#10;  ...    CREATION_DATE                 SEL&amp;#10;" ParentModule="OBJLIB1" Width="10" Required="false" ColumnName="CREATION_DATE" DataType="Date" ParentModuleType="25" Label="Creation Date" ParentType="15" ParentName="QMSSO$QUERY_ONLY_ITEM" MaximumLength="10" PersistentClientInfoLength="142" ParentFilename="tmiolb65_mla.olb" FormatMask="DD-MM-RRRR">

A naive grep command would print out the whole line, including the file name. After some iterations I came to the following command, which does what I want in a single line.

grep -R -h -o -e FormatMask=\"[^\"]* * | sed 's/FormatMask="//g' | sort | uniq

What the command does is:

  • grep recursively (-R) for a regular expression (-e)
  • search for FormatMask="<any-char-until-quotation>
  • print only the matching part of the line (-o). This will include the prefix FormatMask="
  • print without the file name (-h)
  • strip off the prefix with sed
  • sort the results alphabetically
  • remove duplicate lines (uniq)

The result (excerpt)is:

00
09
099
0999
0999999
09999999
0D0
0D999
0D9999
9
90
90D0
90D000
...